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Author Topic: Looking for help on a aaa to 18650 power cell swap  (Read 2894 times)
NekoWan
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« on: May 26, 2017, 06:59:19 PM »

Hello everyone!  I am the proud owner of a Sentinel LE v4 stunt saber, with violet amethyst and a aaa power setup.  I have been looking at upgrading the pack to a single 18650 3400 mah power cell, and am just hoping for a little help with the resistors.

I believe all I need is to put a 2 ohm 1 w resistor on the red, and leave the blue un-resisted, then attach the 18650 holder and done.  Is that all to it or am I missing something?

The purpose of this swap is to get a little more brightness out of my blade.  Thank you in advance for any help  Wink
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Dauntless Seven
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« Reply #1 on: May 26, 2017, 08:13:26 PM »

Hi.  There are many electronically wise and experienced members here such as Racona Nova, JediXIX, Isola, Kouri, RevanReborn.  Hopefully one of them or others not mentioned as the list is long, will respond to your question.  Smiley

Is your intention to replace with another alkaline or change to a protected Li-Ion battery ?
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Jediseth
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« Reply #2 on: May 26, 2017, 08:29:40 PM »

7.4 V  3400 mAh is a pack containing two 18650 cells. You don't need that much battery to run a led. You can just use smaller setup with a buckpuck. Everything you would need is offered here in the US store.
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NekoWan
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« Reply #3 on: May 26, 2017, 08:51:31 PM »

Thank you both for responding Smiley. To clarify though, I plan on running just one 18650 power cell, I agree 2 would be overkill.

The plan is to have just a single 18650 battery holder, one 3.7 18650 3400mah li-ion cell.

The choice on this is setup is I believe a single 3.7 18650 cell will be bright, while not requiring me to need a buckpuck.  Price on this route is also an upside  Cheesy
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Jediseth
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« Reply #4 on: May 26, 2017, 11:05:39 PM »

In that case a 2.7 ohm 3 watt resistor on red should do the trick.
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lovetadraw
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« Reply #5 on: May 26, 2017, 11:08:33 PM »

I'd advise to use a tiny resistor (.47ohm) or so on the blue, it can be bad to leave it completely unresisted even if it's very close
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Jediseth
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« Reply #6 on: May 26, 2017, 11:17:25 PM »

I'd advise to use a tiny resistor (.47ohm) or so on the blue, it can be bad to leave it completely unresisted even if it's very close

If your using a soundboard that would be best. However to maintain a nice purple you would need that resistor on both blue and red. One .5 or .47 ohm resistor on each the blue and the red. As your batteries get weaken in strength your purple will become more pink. Putting just one .47 resistor on blue alone may still just give you pink. With no soundboard I think your okay not to resistor blue. But what Lovetadraw sudgested is not a bad idea.
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NekoWan
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« Reply #7 on: May 27, 2017, 04:10:14 AM »

Thank you so much for all the help! 

Just to clarify, I should put a 2.7ohm 3 watt resistor on red and a .47 to .5 on blue?
Or .47 to .5 on both?

I will most likely due this after the weekend so I can gather the proper resistors.

Anyone know if a local RS would carry em?  Also thank you again, I'm so glad I asked  Cheesy
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scifidude79
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« Reply #8 on: May 27, 2017, 04:23:35 AM »

2.7 Ohm 3w is way more than you need for the red with a 3.7v (single 18650) power source.  To calculate a resistor, you need your source voltage and the forward voltage and current of the LED.  Then you can use this:

http://led.linear1.org/1led.wiz
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Jediseth
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« Reply #9 on: May 27, 2017, 05:35:51 AM »

It is more than he needs for the red led. He's trying to make purple. So the red needs to be resisted farther than needed.

If you add a .47 ohm to the blue your lowering the strength of the blue and making your color more on the pink side of purple by giving the blue less strength.  1/2 an ohm is not much so I'm not sure without trying it myself what it will look like.  I guess it all depends on what shade of purple you want. As long as you don't overload the led you can play around a bit and see what color of purple your looking for.
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Jediseth
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« Reply #10 on: May 27, 2017, 02:04:06 PM »

I'm glad you posted that calculator for him Scifidude, Didn't think to post that.
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scifidude79
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« Reply #11 on: May 27, 2017, 02:20:04 PM »

The VA module that came out of the saber will already have a resistor on the red to make the color.  Mine certainly does.

I just wired up an RGB saber recently with an 18650.  I put 1 Ohm 2W resistors on all of the LEDs, which is plenty for the power source.
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Jediseth
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« Reply #12 on: May 27, 2017, 02:32:47 PM »

I didn't read the fine print. He got the led out of the saber. Well that changes things.  I was thinking the led was his build.

The directions I gave him were exactly for an RGB led if he wanted to obtain a nice purple. Or if he was just running a red and blue. I didn't realize he had a led from US that was already resistored.
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scifidude79
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« Reply #13 on: May 27, 2017, 03:48:04 PM »

It's OK, we all make that mistake from time to time.

Yeah, you definitely need a stronger resist on the red if you want purple.  My RGB saber is very pink with the red and blue mixed with resistors of the same type.
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NekoWan
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« Reply #14 on: May 27, 2017, 06:54:49 PM »

Thank you for all the help everyone!!  I am so glad I asked, I had a feeling this community would be willing to help a fella out.

And special thanks for the calculator, as I am TERRIBLE at math  Sad

So what I have as far as numbers go, 3.7 for the battery, and I believe a US red led has 2.1 forward volts (I think I got that figure somewhere on the forums), and I also believe 700mah forward voltage.

In the calculator I put 3.7, 2.1, 700.
It gives me a resistor of 1.3watt 2.7ohm

I will post before, during and after pics of this little project, and thanks again  Wink. I am super excited to try this out!!
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